5.1 The solution for Re < 0.5

In[26]:=
  Clear[v,m,g,k]
  vsolution1 = 
       DSolve[{m v'[t] == -m g - k v[t],v[0] == v0}, v[t], t]

Out[26]=

                     g m
                     --- + v0
              g m     k
  {{v[t] -> -(---) + --------}}
               k      (k t)/m
                     E

We need to select the right hand side of the above replacement rule.

In[27]:=

  velocity1 = vsolution1[[1,1,2]]

Out[27]=

           g m
           --- + v0
    g m     k
  -(---) + --------
     k      (k t)/m
           E

Now integrate to get y[t].

In[28]:=

  Clear[v,m,g,k]
  ysolution1 = 
       DSolve[{y'[t] == velocity1, y[0] == y0}, y[t], t]

Out[28]=

               2
            g m    g m t   m v0   m (g m + k v0)
  {{y[t] -> ---- - ----- + ---- - -------------- + y0}}
              2      k      k       (k t)/m  2
             k                     E        k

In[29]:=

  Clear[v,m,g,k]
  height1 = ysolution1[[1,1,2]]

Out[29]=

     2
  g m    g m t   m v0   m (g m + k v0)
  ---- - ----- + ---- - -------------- + y0
    2      k      k       (k t)/m  2
   k                     E        k

Up to 5. Solutions of the Differential Equations